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Python: RegEx for matching lines which starts with “ERROR: ”

I have the following error message in a string:
ERROR: register cannot be used to define an enum value

I have the following RegEx:
\AERROR:(\s|.)*?\Z

This regex matches the whole line, but I want it to match only the part which contains ERROR: and the text after ERROR:. I.e. it should match everything before \A and \Z.
The following text is the input text:
ERROR: register cannot be used to define an enum value

1:0004: public:’ALWAYS_ADD’
^

I used the following regex:
new_string = re.sub(r’\AERROR:(\s|.)*?\Z’, ”, old_string)

The expected result is:
1:0004: public:’ALWAYS_ADD’

A:

You could use the following regex:
r’^ERROR:(\s|.)*?\Z’

^ indicates the start of the string and \Z anchor makes sure that, even if there are multiple ERROR lines, only the last one is selected.
DEMO
To get only the line you want, you can use re.findall instead:
import re

string = “””ERROR: register cannot be used to define an enum value

1:0004: public:’ALWAYS_ADD’
^

“””
print(re.findall(r’^ERROR:(\s|.)*?\Z’, string))

You could also use the following regex:
r’^ERROR:(\s|.)*?\Z’

DEMO

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